Reading binary istream byte by byte

Question

I was attempting to read a binary file byte by byte using an ifstream. I've used istream methods like get() before to read entire chunks of a binary file at once without a problem. But my current task lends itself to going byte by byte and relying on the buffering in the io-system to make it efficient. The problem is that I seemed to reach the end of the file several bytes sooner than I should. So I wrote the following test program:

#include <iostream>
#include <fstream>

int main() {
    typedef unsigned char uint8;
    std::ifstream source("test.dat", std::ios_base::binary);
    while (source) {
        std::ios::pos_type before = source.tellg();
        uint8 x;
        source >> x;
        std::ios::pos_type after = source.tellg();
        std::cout << before << ' ' << static_cast<int>(x) << ' '
                  << after << std::endl;
    }
    return 0;
}

This dumps the contents of test.dat, one byte per line, showing the file position before and after.

Sure enough, if my file happens to have the two-byte sequence 0x0D-0x0A (which corresponds to carriage return and line feed), those bytes are skipped.

• I've opened the stream in binary mode. Shouldn't that prevent it from interpreting line separators?
• Do extraction operators always use text mode?
• What's the right way to read byte by byte from a binary istream?

MSVC++ 2008 on Windows.

Answer 1

The >> extractors are for formatted input; they skip white space (by default). For single character unformatted input, you can use istream::get() (returns an int, either EOF if the read fails, or a value in the range [0,UCHAR_MAX]) or istream::get(char&) (puts the character read in the argument, returns something which converts to bool, true if the read succeeds, and false if it fails.