What is the difference between the /Ox and /O2 compiler options?

Cody Gray picture Cody Gray · Feb 21, 2011 · Viewed 23.4k times · Source

Microsoft's C++ compiler (cl.exe, as included with Visual Studio) offers several optimization switches. The difference between most of them seems self-explanatory, but it's not clear to me what the difference is between /O2 (which optimizes code for maximum speed) and /Ox (which selects "full optimization").

I've tried reading the documentation for the /Ox option, and it seems to confirm that this switch also enables optimizations for maximum speed, rather than size:

The /Ox compiler option produces code that favors execution speed over smaller size.

But in particular, the following statement under the "Remarks" section caught my eye:

In general, specify /O2 (Maximize Speed) instead of /Ox.

So my question is, why should one generally favor /O2 over /Ox? Does the latter option enable a particular optimization known to cause unforeseen bugs or otherwise unexpected behavior? Is it simply that the amount of optimization to be gained is not worth the additional compile time? Or is this just a completely meaningless "recommendation" resulting from the fact that /O2 is the default option in VS?

Answer

Asha picture Asha · Feb 21, 2011

I found it here:

Ox and O2 are almost identical. They differ only in the fact that O2 also throws GF and Gy. There is almost no reason to avoid throwing these two switches.