Printing 1 to 1000 without loop or conditionals

Question

Task: Print numbers from 1 to 1000 without using any loop or conditional statements. Don't just write the printf() or cout statement 1000 times.

How would you do that using C or C++?

Answer 1

This one actually compiles to assembly that doesn't have any conditionals:

#include <stdio.h>
#include <stdlib.h>

void main(int j) {
  printf("%d\n", j);
  (&main + (&exit - &main)*(j/1000))(j+1);
}

---

Edit: Added '&' so it will consider the address hence evading the pointer errors.

This version of the above in standard C, since it doesn't rely on arithmetic on function pointers:

#include <stdio.h>
#include <stdlib.h>

void f(int j)
{
    static void (*const ft[2])(int) = { f, exit };

    printf("%d\n", j);
    ft[j/1000](j + 1);
}

int main(int argc, char *argv[])
{
    f(1);
}