Is there a way to distinguish between an assigned (possibly expired) weak_ptr and a non-assigned one.
weak_ptr<int> w1;
weak_ptr<int> w2 = ...;
I understand the following checks for either non-assignment or expiry, but is there a (cheaper?) check for only non-assignment?
if (!w.lock()) { /* either not assigned or expired */ }
You can use two calls to owner_before
to check equality with a default constructed (empty) weak pointer:
template <typename T>
bool is_uninitialized(std::weak_ptr<T> const& weak) {
using wt = std::weak_ptr<T>;
return !weak.owner_before(wt{}) && !wt{}.owner_before(weak);
}
This will only return true
if w{} "==" weak
, where "=="
compares owner, and according to en.cppreference.com:
The order is such that two smart pointers compare equivalent only if they are both empty or if they both own the same object, even if the values of the pointers obtained by get() are different (e.g. because they point at different subobjects within the same object).
Since the default constructor constructs an empty weak pointer, this can only return true
if weak
is also empty. This will not return true
if weak
has expired.
Looking at the generated assembly (with optimization), this seems pretty optimized:
bool is_uninitialized<int>(std::weak_ptr<int> const&):
cmp QWORD PTR [rdi+8], 0
sete al
ret
... compared to checking weak.expired()
:
bool check_expired(std::weak_ptr<int> const&):
mov rdx, QWORD PTR [rdi+8]
mov eax, 1
test rdx, rdx
je .L41
mov eax, DWORD PTR [rdx+8]
test eax, eax
sete al
.L41:
rep ret
... or returning !weak.lock()
(~80 lines of assembly).