C++ Double Address Operator? (&&)

Question

I'm reading STL source code and I have no idea what && address operator is supposed to do. Here is a code example from stl_vector.h:

vector&
operator=(vector&& __x) // <-- Note double ampersands here
{
    // NB: DR 675.
    this->clear();
    this->swap(__x); 
    return *this;
}

Does "Address of Address" make any sense? Why does it have two address operators instead of just one?

Answer 1

&& is new in C++11. int&& a means "a" is an r-value reference. && is normally only used to declare a parameter of a function. And it only takes a r-value expression. If you don't know what an r-value is, the simple explanation is that it doesn't have a memory address. E.g. the number 6, and character 'v' are both r-values. int a, a is an l-value, however (a+2) is an r-value. For example:

void foo(int&& a)
{
    //Some magical code...
}

int main()
{
    int b;
    foo(b); //Error. An rValue reference cannot be pointed to a lValue.
    foo(5); //Compiles with no error.
    foo(b+3); //Compiles with no error.

    int&& c = b; //Error. An rValue reference cannot be pointed to a lValue.
    int&& d = 5; //Compiles with no error.
}

Hope that is informative.