C++ static member variable and its initialization

c++ initialization static-variables
kumar_m_kiran picture kumar_m_kiran · Dec 28, 2010 · Viewed 51.4k times · Source


For static member variables in C++ class - the initialization is done outside the class. I wonder why? Any logical reasoning/constraint for this? Or is it purely legacy implementation - which the standard does not want to correct?

I think having initialization in the class is more "intuitive" and less confusing.It also gives the sense of both static and global-ness of the variable. For example if you see the static const member.

Answer

John Dibling picture John Dibling · Dec 28, 2010

Fundamentally this is because static members must be defined in exactly one translation unit, in order to not violate the One-Definition Rule. If the language were to allow something like:

struct Gizmo
{
  static string name = "Foo";
};

then name would be defined in each translation unit that #includes this header file.

C++ does allow you to define integral static members within the declaration, but you still have to include a definition within a single translation unit, but this is just a shortcut, or syntactic sugar. So, this is allowed:

struct Gizmo
{
  static const int count = 42;
};

So long as a) the expression is const integral or enumeration type, b) the expression can be evaluated at compile-time, and c) there is still a definition somewhere that doesn't violate the one definition rule:

file: gizmo.cpp

#include "gizmo.h"

const int Gizmo::count;

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