How to convert yuy2 to a BITMAP in C++

Question

I'm using a security camera DLL to retreive the image from the camera. The DLL call a function of my program passing the image buffer as a parameter, but the image is in yuy2 format. I need to convert this buffer to RGB, but I tried every formula I found on Internet with no success. Every example I tried (including http://msdn.microsoft.com/en-us/library/aa904813(VS.80).aspx#yuvformats_2) gives me wrong colors.

I'm able to convert the buffer to a BW image using only the Y component of the pixel, but I really need the color picture. I debugged (assembly only) the DLL that shows the image in the screen and it uses DirectDraw to do this.

Answer 1

Using the information from the Microsoft link in the question:

for (int i = 0;  i < width/2;  ++i)
{
    int y0 = ptrIn[0];
    int u0 = ptrIn[1];
    int y1 = ptrIn[2];
    int v0 = ptrIn[3];
    ptrIn += 4;
    int c = y0 - 16;
    int d = u0 - 128;
    int e = v0 - 128;
    ptrOut[0] = clip(( 298 * c + 516 * d + 128) >> 8); // blue
    ptrOut[1] = clip(( 298 * c - 100 * d - 208 * e + 128) >> 8); // green
    ptrOut[2] = clip(( 298 * c + 409 * e + 128) >> 8); // red
    c = y1 - 16;
    ptrOut[3] = clip(( 298 * c + 516 * d + 128) >> 8); // blue
    ptrOut[4] = clip(( 298 * c - 100 * d - 208 * e + 128) >> 8); // green
    ptrOut[5] = clip(( 298 * c + 409 * e + 128) >> 8); // red
    ptrOut += 6;
}