I'm trying to make a table (a 9 by 11 array) that stores the amount of time taken by a function by several sorting functions.
I think I want the table to be a string. I currently cannot solve how to convert chrono
to string
and haven't been able to find any resources online.
Do I need to abandon the string typing for the table, or is there a way to store these time differences in a string?
for (int i = 0; i<8;i++) // sort 8 different arrays
{
start = chrono::system_clock::now();
//Sort Array Here
end = chrono::system_clock::now();
chrono::duration<double> elapsed_seconds = end-start;
table[1][i] = string(elapsed_seconds) // error: no matching conversion for functional style cast
}
You'll need to stream into a std::ostringstream
, and then retrieve the string from that stream.
To stream a chrono::duration
you could use its .count()
member function, and then you might want to add units (e.g. ns
or whatever the unit is).
This free, header-only, open-source library: https://howardhinnant.github.io/date/chrono_io.html makes it easier to stream a duration
by automatically appending the units for you.
For example:
#include "chrono_io.h"
#include <iostream>
#include <sstream>
int
main()
{
using namespace std;
using namespace date;
ostringstream out;
auto t0 = chrono::system_clock::now();
auto t1 = chrono::system_clock::now();
out << t1 - t0;
string s = out.str();
cout << s << '\n';
}
Just output for me:
0µs
Without "chrono_io.h"
it looks more like:
out << chrono::duration<double>(t1 - t0).count() << 's';
There's also the to_string
family that could be used:
string s = to_string(chrono::duration<double>(t1 - t0).count()) + 's';
There is no to_string
that goes directly from a chrono::duration
however. You have to "escape" out with .count()
and then add units (if desired).
C++20 brings the functionality of "chrono_io.h"
straight into <chrono>
. So no longer a need for the free open-source library.