What is an "operator int" function?

c++ terminology conversion-operator
ankit picture ankit · Sep 28, 2010 · Viewed 46.1k times · Source

What is the "operator int" function below? What does it do?

class INT
{
   int a;

public:
   INT(int ix = 0)
   {
      a = ix;
   }

   /* Starting here: */
   operator int()
   {
      return a;
   }
   /* End */

   INT operator ++(int)
   {
      return a++;
   }
};

Answer

John Dibling picture John Dibling · Sep 28, 2010

The bolded code is a conversion operator. (AKA cast operator)

It gives you a way to convert from your custom INT type to another type (in this case, int) without having to call a special conversion function explicitly.

For example, with the convert operator, this code will compile:

INT i(1234);
int i_2 = i; // this will implicitly call INT::operator int()

Without the convert operator, the above code won't compile, and you would have to do something else to go from an INT to an int, such as:

INT i(1234);
int i_2 = i.a;  // this wont compile because a is private

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