I'm getting the following error:
error: cannot convert 'std::basic_string<char>::iterator {aka __gnu_cxx::__normal
_iterator<char*, std::basic_string<char> >}' to 'const char*' for argument '1'
to 'int remove(const char*)'
For some reason, my program compiles perfectly when I'm working on a Mac... but once I use a Linux machine, this error pops up in more than one place.
Here's one of the instances where the error pops up:
SomeClass::SomeClass(string t, string art, Time dur) {
char chars[] = ",";
t.erase(std::remove(t.begin(), t.end(), chars[0]), t.end());
art.erase(std::remove(art.begin(), art.end(), chars[0]), art.end());
// Some more code ...
}
More specifically, the error is coming from this line:
t.erase(std::remove(t.begin(), t.end(), chars[0]), t.end());
Does anyone know how to approach this problem?
You forgot to #include <algorithm>
, where std::remove
is located. Without that, your compiler only knows about this std::remove
(I get the same error with Visual C++ 14), which is defined in indirectly included <cstdio>
header.
Different behavior among compilers is a result of different #include
hierarchies of the standard library implementations.