It's easy to create a new name for a type, a variable or a namespace. But how do I assign a new name to a function? For example, I want to use the name holler
for printf
. #define is obvious... any other way?
Solutions:
#define holler printf
void (*p)() = fn; //function pointer
void (&r)() = fn; //function reference
inline void g(){ f(); }
There are different approaches:
With C++11 with non-template non-overloaded functions you can simply use:
const auto& new_fn_name = old_fn_name;
If this function has multiple overloads you should use static_cast
:
const auto& new_fn_name = static_cast<OVERLOADED_FN_TYPE>(old_fn_name);
Example: there are two overloads of function std::stoi
int stoi (const string&, size_t*, int);
int stoi (const wstring&, size_t*, int);
If you want to make an alias to the first version you should use the following:
const auto& new_fn_name = static_cast<int(*)(const string&, size_t*, int)>(std::stoi);
Note: there is no way to make an alias to overloaded function such that all its overloaded versions work, so you should always specify which exact function overload you want.
With C++14 you can go even further with constexpr
template variables. That allows you to alias templated functions:
template<typename T>
constexpr void old_function(/* args */);
template<typename T>
constexpr auto alias_to_old = old_function<T>;
Moreover, starting with C++11 you have a function called std::mem_fn
that allows to alias member functions. See the following example:
struct A {
void f(int i) {
std::cout << "Argument: " << i << '\n';
}
};
A a;
auto greet = std::mem_fn(&A::f); // alias to member function
// prints "Argument: 5"
greet(a, 5); // you should provide an object each time you use this alias
// if you want to bind an object permanently use `std::bind`
greet_a = std::bind(greet, a, std::placeholders::_1);
greet_a(3); // equivalent to greet(a, 3) => a.f(3);