Do you have to pass delete the same pointer that was returned by new, or can you pass it a pointer to one of the classes base types? For example:
class Base
{
public:
virtual ~Base();
...
};
class IFoo
{
public:
virtual ~IFoo() {}
virtual void DoSomething() = 0;
};
class Bar : public Base, public IFoo
{
public:
virtual ~Bar();
void DoSomething();
...
};
Bar * pBar = new Bar;
IFoo * pFoo = pBar;
delete pFoo;
Of course this is greatly simplified. What I really want to do is create a container full of boost::shared_ptr and pass it to some code that will remove it from the container when it is finished. This code will know nothing of the implementation of Bar or Base, and will rely on the implied delete operator in the shared_ptr destructor to do the right thing.
Can this possibly work? My intuition says no, since the pointers will not have the same address. On the other hand, a dynamic_cast<Bar*> should work, so somewhere the compiler is storing enough information to figure it out.
mov eax, DWORD PTR _this$[ebp]
Tracing the assembler revealed that this was the pointer being passed to the delete function. Mystery solved.
I've fixed the example to add the virtual destructor to IFoo, it was a simple oversight. Thanks again to everyone who pointed it out.
Yes, it will work, if and only if the base class destructor is virtual, which you have done for the Base
base class but not for the IFoo
base class. If the base class destructor is virtual, then when you call operator delete
on the base class pointer, it uses dynamic dispatch to figure out how to delete the object by looking up the derived class destructor in the virtual function table.
In your case of multiple inheritance, it will only work if the base class you're deleting it through has a virtual destructor; it's ok for the other base classes to not have a virtual destructor, but only if you don't try to delete any derived objects via those other base class pointers.