std::map emplace without copying value

Question

The C++11 std::map<K,V> type has an emplace function, as do many other containers.

std::map<int,std::string> m;

std::string val {"hello"};

m.emplace(1, val);

This code works as advertised, emplacing the std::pair<K,V> directly, however it results in a copy of key and val taking place.

Is it possible to emplace the value type directly into the map as well? Can we do better than moving the arguments in the call to emplace?

---

Here's a more thorough example:

struct Foo
{
   Foo(double d, string s) {}
   Foo(const Foo&) = delete;
   Foo(Foo&&) = delete;
}

map<int,Foo> m;
m.emplace(1, 2.3, string("hello")); // invalid

Answer 1

The arguments you pass to map::emplace get forwarded to the constructor of map::value_type, which is pair<const Key, Value>. So you can use the piecewise construction constructor of std::pair to avoid intermediate copies and moves.

std::map<int, Foo> m;

m.emplace(std::piecewise_construct,
          std::forward_as_tuple(1),
          std::forward_as_tuple(2.3, "hello"));

Live demo