Differences between std::make_unique and std::unique_ptr with new

NFRCR picture NFRCR · Mar 22, 2014 · Viewed 58.2k times · Source

Does std::make_unique have any efficiency benefits like std::make_shared?

Compared to manually constructing std::unique_ptr:

std::make_unique<int>(1);         // vs
std::unique_ptr<int>(new int(1));

Answer

bames53 picture bames53 · Mar 22, 2014

The motivation behind make_unique is primarily two-fold:

  • make_unique is safe for creating temporaries, whereas with explicit use of new you have to remember the rule about not using unnamed temporaries.

    foo(make_unique<T>(), make_unique<U>()); // exception safe
    
    foo(unique_ptr<T>(new T()), unique_ptr<U>(new U())); // unsafe*
    
  • The addition of make_unique finally means we can tell people to 'never' use new rather than the previous rule to "'never' use new except when you make a unique_ptr".

There's also a third reason:

  • make_unique does not require redundant type usage. unique_ptr<T>(new T()) -> make_unique<T>()

None of the reasons involve improving runtime efficiency the way using make_shared does (due to avoiding a second allocation, at the cost of potentially higher peak memory usage).

* It is expected that C++17 will include a rule change that means that this is no longer unsafe. See C++ committee papers P0400R0 and P0145R3.