Getting an error "fopen': This function or variable may be unsafe." when compling

c++ opencv fopen
SeverusSwan picture SeverusSwan · Feb 19, 2014 · Viewed 121.1k times · Source

I'm receiving this error when compiling:

'fopen': This function or variable may be unsafe. 
Consider using fopen_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS.

I'm new to C++ and open CV, therefore please help me to get rid of this error.

Thanks

void _setDestination(const char* name)
{
    if (name==NULL) {
        stream = stdout;
    }
    else {
        stream = fopen(name,"w");
        if (stream == NULL) {
            stream = stdout;
        }
    }
}

Answer

nvoigt picture nvoigt · Feb 19, 2014

This is not an error, it is a warning from your Microsoft compiler.

Select your project and click "Properties" in the context menu.

In the dialog, chose Configuration Properties -> C/C++ -> Preprocessor

In the field PreprocessorDefinitions add ;_CRT_SECURE_NO_WARNINGS to turn those warnings off.

Related questions

Find OpenCV Version Installed on Ubuntu

I would like to find out what version of OpenCV is installed on my computer (i am running Ubuntu 10.04). Is there a simple way to check it if ? If not then can i find out the directories where files (samples, …

Read More
Image Processing: Algorithm Improvement for 'Coca-Cola Can' Recognition

One of the most interesting projects I've worked on in the past couple of years was a project about image processing. The goal was to develop a system to be able to recognize Coca-Cola 'cans' (note that I'm stressing the …

Read More
OpenCV get pixel channel value from Mat image

Maybe I'm not looking hard enough, but everything seems to want me to use an array. Thus, how do I get the channel value for a particular pixel for foo if foo is something like Mat foo = imread("bar.png")?

Read More