How to display a fixed number of digits in C++ without rounding

user2529011 picture user2529011 · Nov 3, 2013 · Viewed 14.1k times · Source

I have this code (very basic):

#include <iostream>
#include <iomanip>

using namespace std;
int main()
{
float   a = 0.0,
        b = 0.0,
        c = 0.0;

cout<<"Input a: ";
cin>>a;
cout<<"input b: ";
cin>>b;
cout<<endl;
c = a / b;

cout<<"Result: "<<fixed<<setprecision(2)<<c<<endl;
return 0;
}

When I enter two numbers (say, a = 513 and b = 791) I get 0.65. Calculator shows that the correct answer is 0.648. I understand that my code rounds up the last decimal number but this is not what I want.

How can I get it to where it just stays as 0.64 and not 0.65?

Answer

Sergey Kalinichenko picture Sergey Kalinichenko · Nov 3, 2013

If you would like to truncate the value to two decimal places, you can multiply it by 100, truncate to integer, and then divide by 100, like this:

c = a / b;
c = floor(100 * c) / 100;
cout<<"Result: "<<fixed<<setprecision(2)<<c<<endl;

Demo on ideone.