I have a class with a unique_ptr member.
class Foo {
private:
std::unique_ptr<Bar> bar;
...
};
The Bar is a third party class that has a create() function and a destroy() function.
If I wanted to use a std::unique_ptr
with it in a stand alone function I could do:
void foo() {
std::unique_ptr<Bar, void(*)(Bar*)> bar(create(), [](Bar* b){ destroy(b); });
...
}
Is there a way to do this with std::unique_ptr
as a member of a class?
Assuming that create
and destroy
are free functions (which seems to be the case from the OP's code snippet) with the following signatures:
Bar* create();
void destroy(Bar*);
You can write your class Foo
like this
class Foo {
std::unique_ptr<Bar, void(*)(Bar*)> ptr_;
// ...
public:
Foo() : ptr_(create(), destroy) { /* ... */ }
// ...
};
Notice that you don't need to write any lambda or custom deleter here because destroy
is already a deleter.