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Would you use num%2 or num&1 to check if a number is even?
Well, there are at least two low-level ways of determining whether a given number is even or not:
1. if (num%2 == 0) { /* even */ }
2. if ((num&1) == 0) { /* even */ }
I consider the second option to be far more elegant and meaningful, and that's the …