How to declare a Qt signal in an abstract class / interface when the implementing class is already derrived from QObject/QWidget?
class IEmitSomething
{
public:
// this should be the signal known to others
virtual void someThingHappened() = 0;
}
class ImplementEmitterOfSomething : public QWidget, public IEmitSomething
{
// signal implementation should be generated here
signals: void someThingHappended();
}
As I found out in the last days... the Qt way of doing this is like this:
class IEmitSomething
{
public:
virtual ~IEmitSomething(){} // do not forget this
signals: // <- ignored by moc and only serves as documentation aid
// The code will work exactly the same if signals: is absent.
virtual void someThingHappened() = 0;
}
Q_DECLARE_INTERFACE(IEmitSomething, "IEmitSomething") // define this out of namespace scope
class ImplementEmitterOfSomething : public QWidget, public IEmitSomething
{
Q_OBJECT
Q_INTERFACES(IEmitSomething)
signals:
void someThingHappended();
}
Now you can connect to those interface signals.
If you don't have access to the implementation when connecting to the signal your connect statement will require a dynamic cast to QObject
:
IEmitSomething* es = ... // your implementation class
connect(dynamic_cast<QObject*>(es), SIGNAL(someThingHappended()), ...);
... and this way you're not forced to expose the implementation class to subscribers and clients. Yeah!!!