c++ template partial specialization member function

Simon Righley picture Simon Righley · Mar 13, 2013 · Viewed 30.3k times · Source

I'm new to templates so maybe this is a trivial thing but I cannot get it to work. I'm trying to get partial specialization of a class member function. The shortest code would be:

template <typename T, int nValue> class Object{
private:
    T m_t;
    Object();
public:
    Object(T t): m_t(t) {}
    T Get() { return m_t; } 
    Object& Deform(){ 
        m_t*=nValue; 
        return *this;
    }
};

template <typename T>
Object<T,0>& Object<T,0>::Deform(){
    this->m_t = -1;
    return *this;
}

int main(){
    Object<int,7> nObj(1);
    nObj.Deform();
    std::cout<<nObj.Get();
}

I tried with nonmember functions and that's worked fine. What also works fine is full specialization of a member function.

But, whenever I try with partial spec. of a member function I get error of the form:

PartialSpecification_MemberFu.cpp(17): error: template argument
list must match the parameter list Object<T,0>& Object<T,0>::Deform().

Would appreciate any help :-)

Answer

Yuushi picture Yuushi · Mar 13, 2013

You cannot partially specialize only a single member function, you must partially specialize the whole class. Hence you'll need something like:

template <typename T>
class Object<T, 0>
{
private:
    T m_t;
    Object();
public:
    Object(T t): m_t(t) {}
    T Get() { return m_t; } 
    Object& Deform()
    {
        std::cout << "Spec\n";
        m_t = -1;
        return *this;
    }
};