From what I understand, you write your Linux Daemon that listens to a request in an endless loop.
Something like..
int main() {
while(1) {
//do something...
}
}
ref: http://www.thegeekstuff.com/2012/02/c-daemon-process/
I read that sleeping a program makes it go into waiting mode so it doesn't eat up resources.
1.If I want my daemon to check for a request every 1 second, would the following be resource consuming?
int main() {
while(1) {
if (request) {
//do something...
}
sleep(1)
}
}
2.If I were to remove the sleep, does it mean the CPU consumption will go up 100%?
3.Is it possible to run an endless loop without eating resources? Say..if it does nothing but just loops itself. Or just sleep(1).
Endless loops and CPU resources is a mystery to me.
Is it possible to run an endless loop without eating resources? Say..if it does nothing but just loops itself. Or just sleep(1).
There ia a better option.
You can just use a semaphore, which remains blocked at the begining of loop and you can signal the semaphore whenever you want the loop to execute.
Note that this will not eat any resources.