I am attempting to override the <<
operator for a class. The purpose is basically to implement a toString()
like behavior for my class, so that sending it to cout
will produce useful output. Using a dummy example, I have the code below. When I attempt to compile, I get the foollowing error:
$ g++ main.cpp Rectangle.cpp
/tmp/ccWs2n6V.o: In function `operator<<(std::basic_ostream<char, std::char_traits<char> >&, CRectangle const&)':
Rectangle.cpp:(.text+0x0): multiple definition of `operator<<(std::basic_ostream<char, std::char_traits<char> >&, CRectangle const&)'
/tmp/ccLU2LLE.o:main.cpp:(.text+0x0): first defined here
I can't figure out why this is happening. my code is below:
Rectangle.h:
#include <iostream>
using namespace std;
class CRectangle {
private:
int x, y;
friend ostream& operator<<(ostream& out, const CRectangle& r);
public:
void set_values (int,int);
int area ();
};
ostream& operator<<(ostream& out, const CRectangle& r){
return out << "Rectangle: " << r.x << ", " << r.y;
}
Rectangle.cpp:
#include "Rectangle.h"
using namespace std;
int CRectangle::area (){
return x*y;
}
void CRectangle::set_values (int a, int b) {
x = a;
y = b;
}
main.cpp:
#include <iostream>
#include "Rectangle.h"
using namespace std;
int main () {
CRectangle rect;
rect.set_values (3,4);
cout << "area: " << rect.area();
return 0;
}
You're breaking the one definition rule. A quick-fix is:
inline ostream& operator<<(ostream& out, const CRectangle& r){
return out << "Rectangle: " << r.x << ", " << r.y;
}
Others are:
Rectangle.cpp
file..
class CRectangle {
private:
int x, y;
public:
void set_values (int,int);
int area ();
friend ostream& operator<<(ostream& out, const CRectangle& r){
return out << "Rectangle: " << r.x << ", " << r.y;
}
};
Bonus:
using namespace std;
from the header.