How do I open a window on a new thread?

mikey555 picture mikey555 · Jan 22, 2012 · Viewed 13.9k times · Source

I have a options window and a window that displays color based on these options and Kinect data. So far everything's on one thread (as far as I know; I haven't done any threading).

Now, I'm adding an option to open a viewer window that will need to be updated with lowest possible latency. All this entails is creating a window and showing it:

viewer = new SkeletalViewer.MainWindow();
viewer.Show();

When this event fires, the color window stops displaying colors (i.e. the event that fires 30 times a second on the main thread stops firing), but the viewer is displayed perfectly. I want the viewer and the color window to both be updated.

From reading other questions, it sounds like the solution is to create the viewer on a new thread. I'm encountering a lot of problems with this, though.

This fires when I click the button to open the viewer:

private void launchViewerThread_Click(object sender, RoutedEventArgs e)
    {
        Thread viewerThread = new Thread(delegate()
        {
            viewer = new SkeletalViewer.MainWindow();
            viewer.Dispatcher.Invoke(new Action(delegate() 
                {
                    viewer.Show();
                }));
        });

        viewerThread.SetApartmentState(ApartmentState.STA); // needs to be STA or throws exception
        viewerThread.Start();

    }

Regardless of if I just call viewer.Show() or Invoke() it as above, the line throws an exception: Cannot use a DependencyObject that belongs to a different thread than its parent Freezable. Here's how I understand Invoke(): it accesses viewer's dispatcher, which knows what thread the object is running on, and can then call methods from that thread.

Should I be trying to put this viewer on a new thread? Is the problem even a question of threads? The user will not be interacting with the viewer.

Anyone know why this doesn't work? Thanks for the help.

Answer

shf301 picture shf301 · Jan 22, 2012

You need to call Show() on the same thread that the window is created on - that's why you are getting the error. Then you also need to start a new Dispatcher instance to get the runtime to manage the window.

private void launchViewerThread_Click(object sender, RoutedEventArgs e)
{
    Thread viewerThread = new Thread(delegate()
    {
        viewer = new SkeletalViewer.MainWindow();
        viewer.Show();
        System.Windows.Threading.Dispatcher.Run();
    });

    viewerThread.SetApartmentState(ApartmentState.STA); // needs to be STA or throws exception
    viewerThread.Start();
}

See the Multiple Windows/Multiple Threads example at: http://msdn.microsoft.com/en-us/library/ms741870.aspx