Out parameters and exceptions

Niklas picture Niklas · Jan 18, 2012 · Viewed 7.9k times · Source

Say I have the following code:

    static void Fjuk(out string str)
    {
        str = "fjuk!";
        throw new Exception();
    }

    static void Main(string[] args)
    {
        string s = null;
        try
        {
            Fjuk(out s);
        }
        catch (Exception)
        {
            Console.WriteLine(s ?? "");
        }
    }

When I test it, s has been initialized to "fjuk!" when it's used in the catch block.
Is this guaranteed by specification or is it implementation dependent? (I have searched the C# 3 spec but couldn't find out myself)

Answer

Marc Gravell picture Marc Gravell · Jan 18, 2012

Pretty much, that is an aspect of what out means; firstly, note that out doesn't really exist - we only really need to consider ref (out is just ref with some "definite assignment" tweaks at the compiler). ref means "pass the address of this" - if we change the value via the address, then that shows immediately - it is, after all, updating the memory on the stack of Main. It can't abstract this (to delay the write) because the value could be, for example, some oversized struct that is using ref specifically for the purpose of avoiding copying it on the stack (an approach used extensively in XNA etc).