How to pass a parameter as a reference with MethodInfo.Invoke

Question

How can I pass a parameter as a reference with MethodInfo.Invoke?

This is the method I want to call:

private static bool test(string str, out byte[] byt)

I tried this but I failed:

byte[] rawAsm = new byte[]{};
MethodInfo _lf = asm.GetType().GetMethod("test", BindingFlags.Static |  BindingFlags.NonPublic);
bool b = (bool)_lf.Invoke(null, new object[]
{
    "test",
    rawAsm
});

The bytes returned are null.

Answer 1

You need to create the argument array first, and keep a reference to it. The out parameter value will then be stored in the array. So you can use:

object[] arguments = new object[] { "test", null };
MethodInfo method = ...;
bool b = (bool) method.Invoke(null, arguments);
byte[] rawAsm = (byte[]) arguments[1];

Note how you don't need to provide the value for the second argument, because it's an out parameter - the value will be set by the method. If it were a ref parameter (instead of out) then the initial value would be used - but the value in the array could still be replaced by the method.

Short but complete sample:

using System;
using System.Reflection;

class Test
{
    static void Main()
    {
        object[] arguments = new object[1];
        MethodInfo method = typeof(Test).GetMethod("SampleMethod");
        method.Invoke(null, arguments);
        Console.WriteLine(arguments[0]); // Prints Hello
    }

    public static void SampleMethod(out string text)
    {
        text = "Hello";
    }
}