C#/.NET - WinForms - Instantiate a Form without showing it

BuddyJoe picture BuddyJoe · Apr 30, 2009 · Viewed 27.2k times · Source

I am changing the Visibility of a Form to false during the load event AND the form still shows itself. What is the right event to tie this.Visible = false; to? I'd like to instantiate the Form1 without showing it.

using System;
using System.Windows.Forms;

namespace TestClient
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }

        private void Form1_Load(object sender, EventArgs e)
        {
            this.Visible = false;
        }

    }
}

Answer

Fredrik Mörk picture Fredrik Mörk · Apr 30, 2009

Regardless of how much you try to set the Visible property before the form has been shown, it will pop up. As I understand it, this is because it is the MainForm of the current ApplicationContext. One way to have the form automatically load, but not show at application startup is to alter the Main method. By default, it looks something like this (.NET 2.0 VS2005):

[STAThread]
static void Main()
{
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);
    Application.Run(new Form1());
}

If you instead do something like this, the application will start, load your form and run, but the form will not show:

[STAThread]
static void Main()
{
    Application.EnableVisualStyles();
    Application.SetCompatibleTextRenderingDefault(false);
    Form1 f = new Form1();
    Application.Run();        

}

I am not entirely sure how this is useful, but I hope you know that ;o)

Update: it seems that you do not need to set the Visible property to false, or supply an ApplicationContext instance (that will be automatically created for you "under the hood"). Shortened the code accordingly.