I'm new with regular expressions. I need to extract the path from the following lines:
XXXX c:\mypath1\test
YYYYYYY c:\this is other path\longer
ZZ c:\mypath3\file.txt
I need to implement a method that return the path of a given line. The first column is a word with 1 or more characters, never is empty, the second column is the path. The separator could be 1 or more spaces, or one or more tabs, or both.
It sounds to me like you just want
string[] bits = line.Split(new char[] { '\t', ' ' }, 2,
StringSplitOptions.RemoveEmptyEntries);
// TODO: Check that bits really has two entries
string path = bits[1];
(This is assuming that the first column never contains spaces or tabs.)
EDIT: As a regular expression you can probably just do:
Regex regex = new Regex(@"^[^ \t]+[ \t]+(.*)$");
Sample code:
using System;
using System.Text.RegularExpressions;
class Program
{
static void Main(string[] args)
{
string[] lines =
{
@"XXXX c:\mypath1\test",
@"YYYYYYY c:\this is other path\longer",
@"ZZ c:\mypath3\file.txt"
};
foreach (string line in lines)
{
Console.WriteLine(ExtractPathFromLine(line));
}
}
static readonly Regex PathRegex = new Regex(@"^[^ \t]+[ \t]+(.*)$");
static string ExtractPathFromLine(string line)
{
Match match = PathRegex.Match(line);
if (!match.Success)
{
throw new ArgumentException("Invalid line");
}
return match.Groups[1].Value;
}
}