I have a Generic Type Interface and want a constructor of an object to take in the Generic Interface.
Like:
public Constructor(int blah, IGenericType<T> instance)
{}
I want the code that creates this object to specify the IGenericType (use Inversion of Control). I have not seen a way for this to happen. Any suggestions to accomplish this?
I want someone to create the object like:
Constructor varname = new Constructor(1, new GenericType<int>());
You can't make constructors generic, but you can use a generic static method instead:
public static Constructor CreateInstance<T>(int blah, IGenericType<T> instance)
and then do whatever you need to after the constructor, if required. Another alternative in some cases might be to introduce a non-generic interface which the generic interface extends.
EDIT: As per the comments...
If you want to save the argument into the newly created object, and you want to do so in a strongly typed way, then the type must be generic as well.
At that point the constructor problem goes away, but you may want to keep a static generic method anyway in a non-generic type: so you can take advantage of type inference:
public static class Foo
{
public static Foo<T> CreateInstance<T>(IGenericType<T> instance)
{
return new Foo<T>(instance);
}
}
public class Foo<T>
{
public Foo(IGenericType<T> instance)
{
// Whatever
}
}
...
IGenericType<string> x = new GenericType<string>();
Foo<string> noInference = new Foo<string>(x);
Foo<string> withInference = Foo.CreateInstance(x);