WPF IOException Cannot locate resource

lace.john picture lace.john · Jun 29, 2011 · Viewed 60.7k times · Source

I have a WPF application.

The page that opens when the app runs in MainWindow.xaml, as set in the StartupUri attribute of the App.xaml file. This page opens fine.

However, if I try to open any other windows using the Show or ShowDialog method I get an IOException in the InitializeComponent method saying "Cannot locate resource 'Window1.xaml'" (or whatever the file is called). This happens with every single window I create. I've searched online but all the solutions seem to say "make sure the StartupUri attribute of the App.xaml is correct" and mine is, hence MainWindow opening.

Any idea what's going on?

Answer

MoonKnight picture MoonKnight · Mar 18, 2013

The above did not work for me but what did work was as follows. Open up the App.xaml

<Application x:Class="dotDiff2013.App"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             StartupUri="MainWindow.xaml">
    <Application.Resources>
    </Application.Resources>
</Application>

You then need to change the start-up URI to the fully qualified one. In my case I had moved my MainWindow.xaml to a folder called 'Main', so changing the above URI to

StartupUri="Main/MainWindow.xaml"

Solved my issue.