How to globally set default options for System.Text.Json.JsonSerializer?

Trevor Reid picture Trevor Reid · Oct 10, 2019 · Viewed 14.1k times · Source

Instead of this:

JsonSerializerOptions options = new JsonSerializerOptions
{
    PropertyNamingPolicy = JsonNamingPolicy.CamelCase
    // etc.
};
var so = JsonSerializer.Deserialize<SomeObject>(someJsonString, options);

I would like to do something like this:

// This property is a pleasant fiction
JsonSerializer.DefaultSettings = new JsonSerializerOptions
{
    PropertyNamingPolicy = JsonNamingPolicy.CamelCase
    // etc.
};

// This uses my options
var soA = JsonSerializer.Deserialize<SomeObject>(someJsonString); 

// And somewhere else in the same codebase...
// This also uses my options
var soB = JsonSerializer.Deserialize<SomeOtherObject>(someOtherJsonString); 

The hope is to not have to pass an instance of JsonSerializerOptions for our most common cases, and override for the exception, not the rule.

As indicated in this q & a, this is a useful feature of Json.Net. I looked in the documentation for System.Text.Json as well as this GitHub repo for .NET Core. And this one.

There doesn't seem to be an analog for managing JSON serialization defaults in .NET Core 3. Or am I overlooking it?


Answer

ps2goat picture ps2goat · Oct 11, 2019

You can create an extension method. Here's an example

I use separate methods vs having to build special settings, so that all the settings will be in a single spot and easily reusable.

public static class DeserializeExtensions
{
    private static JsonSerializerOptions defaultSerializerSettings = new JsonSerializerOptions();

    // set this up how you need to!
    private static JsonSerializerOptions featureXSerializerSettings = new JsonSerializerOptions();


    public static T Deserialize<T>(this string json)
    {       
        return JsonSerializer.Deserialize<T>(json, defaultSerializerSettings);
    }

    public static T DeserializeCustom<T>(this string json, JsonSerializerOptions settings)
    {
        return JsonSerializer.Deserialize<T>(json, settings);
    }

    public static T DeserializeFeatureX<T>(this string json)
    {
        return JsonSerializer.Deserialize<T>(json, featureXSerializerSettings);
    }
}

Then you call it as a method on a string, whether literal or a variable.

    Car result = @"{""Wheels"": 4, ""Doors"": 2}".DeserializeFeatureX<Car>();