Most efficient way to check if an object is a value type

Question

WARNING: THIS CODE SUCKS, SEE ANTHONY'S COMMENTS

Which is faster?

1.

  public bool IsValueType<T>(T obj){
       return obj is ValueType;
  }

2.

  public bool IsValueType<T>(T obj){
       return obj == null ? false : obj.GetType().IsValueType;
  } 

3.

  public bool IsValueType<T>(T obj){
       return default(T) != null;
  }

4.Something else

Answer 1

You aren't really testing an object - you want to test the type. To call those, the caller must know the type, but... meh. Given a signature <T>(T obj) the only sane answer is:

public bool IsValueType<T>() {
    return typeof(T).IsValueType;
}

or if we want to use an example object for type inference purposes:

public bool IsValueType<T>(T obj) {
    return typeof(T).IsValueType;
}

this doesn't need boxing (GetType() is boxing), and doesn't have problems with Nullable<T>. A more interesting case is when you are passing object...

 public bool IsValueType(object obj);

here, we already have massive problems with null, since that could be an empty Nullable<T> (a struct) or a class. But A reasonable attempt would be:

public bool IsValueType(object obj) {
    return obj != null && obj.GetType().IsValueType;
}

but note that it is incorrect (and unfixable) for empty Nullable<T>s. Here it becomes pointless to worry about boxing as we are already boxed.