How To Make a Tetris Clone?

Brock Woolf picture Brock Woolf · Feb 19, 2009 · Viewed 11k times · Source

I am working on coding a Tetris clone in XNA C# and am unsure of the best way to approach the data structure side of the game on a high level.

I am totally fine with the collision detection, rotations, animation etc. What I need to know the best way to do the storing of "dropped blocks" - ie blocks that are no longer under tha player's control.

I think that each Tetromino block should be stored in its own class that consists of a 4x4 array so that the block can easily be rotated. The problem is then how to I store the tetromino's final position into the game grid by then cutting the tetromino up into individual blocks(for each cell) and then set the main game grid's corresponding positions to hold these same blocks, then disappearing the tetromino once it has reached its final position. Maybe there is some drawback to my method.

Should I create a 10x20 matrix for the main game grid which can then store? or should I use stacks or queues to somehow store the dropped blocks. Or maybe there is some better method/data structure to store things?

I am sure my way would work, but I am reaching out to see if anybody knows a better way or if my way is good enough?

P.S. Not homework, this will be a project for my portfolio. Thanks.

Answer

Dan Lew picture Dan Lew · Feb 19, 2009

Once a block is immobile, there's nothing that distinguishes it from any other block that is now immobile. In that regard, I think it makes the most sense to store the entire grid as a matrix, where each square is either filled or not (along with the color of the block if it is).

I feel like the matrix has many advantages. It'll make collision detection simple (no having to compare with multiple objects, just locations on a matrix). Storing it as a matrix will also make it easier to determine when a full line has been created. On top of that, you don't have to worry about splicing an immobile Tetromino when a line disappears. And when one does, you can just shift the entire matrix down in one fell swoop.