I am trying to create process on a remote machine using using System.Diagnostics.Process class.
I am able to create a process. But the problem is, creating a service is take a long time and console window is displayed.
Another annoying thing is the console window is displayed on top of my windows form and i cant do any other operations on that form.
I have set all properties like CreateNoWindow = true
,
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden
but still it shows the console window. even i have redirected output and errors to seperate stream but no luck.
Is there any other way to hide the Console window? Please help me out .
Here is the part of my code i used to execute sc command.
Process proc = new Process();
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
proc.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
proc.StartInfo.FileName = "sc";
proc.StartInfo.Arguments = string.Format(@"\\SYS25 create MySvc binPath= C:\mysvc.exe");
proc.StartInfo.RedirectStandardError = false;
proc.StartInfo.RedirectStandardOutput = false;
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.CreateNoWindow = true;
proc.Start();
proc.WaitForExit();
I had a similar issue when attempting to start a process without showing the console window. I tested with several different combinations of property values until I found one that exhibited the behavior I wanted.
Here is a page detailing why the UseShellExecute
property must be set to false.
http://msdn.microsoft.com/en-us/library/system.diagnostics.processstartinfo.createnowindow.aspx
Under Remarks section on page:
If the UseShellExecute property is true or the UserName and Password properties are not null, the CreateNoWindow property value is ignored and a new window is created.
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = fullPath;
startInfo.Arguments = args;
startInfo.RedirectStandardOutput = true;
startInfo.RedirectStandardError = true;
startInfo.UseShellExecute = false;
startInfo.CreateNoWindow = true;
Process processTemp = new Process();
processTemp.StartInfo = startInfo;
processTemp.EnableRaisingEvents = true;
try
{
processTemp.Start();
}
catch (Exception e)
{
throw;
}