I have a object {System.Collections.Generic.List<object>}
that contains 1000 object {DynamicData}
inside of it, each one with 4 keys and values and one more List
with 2 keys and values inside.
I need to serialize this object into a XML File, i tried normal serialization but it gives me this exception = The type DynamicData was not expected
, how can i serialize this object?
Here is the code:
//output is the name of my object
XmlSerializer xsSubmit = new XmlSerializer(output.GetType());
var xml = "";
using (var sww = new StringWriter())
{
using (XmlWriter writers = XmlWriter.Create(sww))
{
try
{
xsSubmit.Serialize(writers, output);
}
catch (Exception ex)
{
throw;
}
xml = sww.ToString(); // Your XML
}
}
I can create the xml file writing line by line and element by element, but i want something more faster and with less code. The structure of my object is like this:
output (count 1000)
[0]
Costumer - "Costumername"
DT - "Date"
Key - "Key"
Payment - "x"
[0]
Adress - "x"
Number - "1"
[1]...
[2]...
You can implement your own serialize object by using IXmlSerializable
[Serializable]
public class ObjectSerialize : IXmlSerializable
{
public List<object> ObjectList { get; set; }
public XmlSchema GetSchema()
{
return new XmlSchema();
}
public void ReadXml(XmlReader reader)
{
}
public void WriteXml(XmlWriter writer)
{
foreach (var obj in ObjectList)
{
//Provide elements for object item
writer.WriteStartElement("Object");
var properties = obj.GetType().GetProperties();
foreach (var propertyInfo in properties)
{
//Provide elements for per property
writer.WriteElementString(propertyInfo.Name, propertyInfo.GetValue(obj).ToString());
}
writer.WriteEndElement();
}
}
}
Usage;
var output = new List<object>
{
new { Sample = "Sample" }
};
var objectSerialize = new ObjectSerialize
{
ObjectList = output
};
XmlSerializer xsSubmit = new XmlSerializer(typeof(ObjectSerialize));
var xml = "";
using (var sww = new StringWriter())
{
using (XmlWriter writers = XmlWriter.Create(sww))
{
try
{
xsSubmit.Serialize(writers, objectSerialize);
}
catch (Exception ex)
{
throw;
}
xml = sww.ToString(); // Your XML
}
}
Output
<?xml version="1.0" encoding="utf-16"?>
<ObjectSerialize>
<Object>
<Sample>Sample</Sample>
</Object>
</ObjectSerialize>
Note : Be careful with that, if you want to deserialize with same type (ObjectSerialize) you should provide
ReadXml
. And if you want to specify schema, you should provideGetSchema
too.