How to serialize dynamic object to xml c#

Lucio Zenir picture Lucio Zenir · Dec 11, 2017 · Viewed 7.6k times · Source

I have a object {System.Collections.Generic.List<object>} that contains 1000 object {DynamicData} inside of it, each one with 4 keys and values and one more List with 2 keys and values inside. I need to serialize this object into a XML File, i tried normal serialization but it gives me this exception = The type DynamicData was not expected, how can i serialize this object?

Here is the code:

           //output is the name of my object
            XmlSerializer xsSubmit = new XmlSerializer(output.GetType());
            var xml = "";

            using (var sww = new StringWriter())
            {
                using (XmlWriter writers = XmlWriter.Create(sww))
                {
                    try
                    {
                        xsSubmit.Serialize(writers, output);
                    }
                    catch (Exception ex)
                    {

                        throw;
                    }
                    xml = sww.ToString(); // Your XML
                }
            }

I can create the xml file writing line by line and element by element, but i want something more faster and with less code. The structure of my object is like this:

output (count 1000)
 [0]
   Costumer - "Costumername"
   DT - "Date"
   Key - "Key"
   Payment - "x"
   [0]
    Adress - "x"
    Number - "1"
 [1]...
 [2]...

Answer

lucky picture lucky · Dec 11, 2017

You can implement your own serialize object by using IXmlSerializable

[Serializable]
public class ObjectSerialize :  IXmlSerializable
{
    public List<object> ObjectList { get; set; }

    public XmlSchema GetSchema()
    {
        return new XmlSchema();
    }

    public void ReadXml(XmlReader reader)
    {

    }

    public void WriteXml(XmlWriter writer)
    {
        foreach (var obj in ObjectList)
        {   
            //Provide elements for object item
            writer.WriteStartElement("Object");
            var properties = obj.GetType().GetProperties();
            foreach (var propertyInfo in properties)
            {   
                //Provide elements for per property
                writer.WriteElementString(propertyInfo.Name, propertyInfo.GetValue(obj).ToString());
            }
            writer.WriteEndElement();
        }
    }
}

Usage;

        var output = new List<object>
        {
            new { Sample = "Sample" }
        };
        var objectSerialize = new ObjectSerialize
        {
            ObjectList = output
        };
        XmlSerializer xsSubmit = new XmlSerializer(typeof(ObjectSerialize));
        var xml = "";

        using (var sww = new StringWriter())
        {
            using (XmlWriter writers = XmlWriter.Create(sww))
            {
                try
                {
                    xsSubmit.Serialize(writers, objectSerialize);
                }
                catch (Exception ex)
                {

                    throw;
                }
                xml = sww.ToString(); // Your XML
            }
        }

Output

<?xml version="1.0" encoding="utf-16"?>
<ObjectSerialize>
    <Object>
        <Sample>Sample</Sample>
    </Object>
</ObjectSerialize>

Note : Be careful with that, if you want to deserialize with same type (ObjectSerialize) you should provide ReadXml. And if you want to specify schema, you should provide GetSchema too.