I have a few C# Azure Functions that run on a schedule using timer triggers. I've set them up like so, where %TimerSchedule%
refers to a cron expression in the app settings:
public static void Run([TimerTrigger("%TimerSchedule%")]TimerInfo myTimer, TraceWriter log)
During development, I often want to run the functions locally using Azure Functions Tools for Visual Studio + Azure Functions Core Tools. But when I hit F5 to debug the function locally it (usually) doesn't run immediately. Instead, it starts waiting for the next occurrence as per the timer schedule. So for example, if my cron expression says to run daily at 8PM, I'd have to wait until 8PM for the function to actually run on my machine.
So my question is: What is the simplest and best way to make a function run once locally?
Things I have tried or considered:
Run()
method
TimerInfo
and TraceWriter
arguments to Run()
– and I've found surprisingly little documentation for that. Microsoft's Strategies for testing your code in Azure Functions page is not very helpful on this topic – it only mentions timer triggers as a way to test other trigger types.
In a perfect world, I'd hit F5 and the function would immediately run once – just like developing a "normal" .NET app.
You could perhaps use the RunOnStartup
flag as documented here. It doesn't quite meet your brief regarding it only running once, but it should at least execute it locally once the app has started.
/// Gets or sets a value indicating whether the function should be invoked /// immediately on startup. After the initial startup run, the function will /// be run on schedule thereafter.
Example using attribute binding:
[TimerTrigger("%TimerSchedule%", RunOnStartup = true)]TimerInfo myTimer