Just threw together a simple test, not for any particular reason other than I like to try to have tests for all my methods even though this one is quite straightforward, or so I thought.
[TestMethod]
public void Test_GetToolRating()
{
var rating = GetToolRating(45.5, 0);
Assert.IsNotNull(rating);
}
private static ToolRating GetToolRating(double total, int numberOf)
{
var ratingNumber = 0.0;
try
{
var tot = total / numberOf;
ratingNumber = Math.Round(tot, 2);
}
catch (Exception ex)
{
var errorMessage = ex.Message;
//log error here
//var logger = new Logger();
//logger.Log(errorMessage);
}
return GetToolRatingLevel(ratingNumber);
}
As you can see in the test method, I AM dividing by zero. The problem is, it doesn't generate an error. See the error window display below.
Instead of an error it is giving a value of infinity? What am I missing?So I googled and found that doubles divided by zero DON'T generate an error they either give null or infinity. The question becomes then, how does one test for an Infinity return value?
You are going to have DivideByZeroException
only in case of integer values:
int total = 3;
int numberOf = 0;
var tot = total / numberOf; // DivideByZeroException thrown
If at least one argument is a floating point value (double
in the question) you'll have FloatingPointType.PositiveInfinity as a result (double.PositiveInfinity
in the context) and no exception
double total = 3.0;
int numberOf = 0;
var tot = total / numberOf; // tot is double, tot == double.PositiveInfinity