Comparing two byte arrays in .NET

Hafthor picture Hafthor · Sep 4, 2008 · Viewed 330.1k times · Source

How can I do this fast?

Sure I can do this:

static bool ByteArrayCompare(byte[] a1, byte[] a2)
{
    if (a1.Length != a2.Length)
        return false;

    for (int i=0; i<a1.Length; i++)
        if (a1[i]!=a2[i])
            return false;

    return true;
}

But I'm looking for either a BCL function or some highly optimized proven way to do this.

java.util.Arrays.equals((sbyte[])(Array)a1, (sbyte[])(Array)a2);

works nicely, but it doesn't look like that would work for x64.

Note my super-fast answer here.

Answer

aku picture aku · Sep 4, 2008

You can use Enumerable.SequenceEqual method.

using System;
using System.Linq;
...
var a1 = new int[] { 1, 2, 3};
var a2 = new int[] { 1, 2, 3};
var a3 = new int[] { 1, 2, 4};
var x = a1.SequenceEqual(a2); // true
var y = a1.SequenceEqual(a3); // false

If you can't use .NET 3.5 for some reason, your method is OK.
Compiler\run-time environment will optimize your loop so you don't need to worry about performance.