The following code is suppose to open CMD from my C# application and open the file text.txt.
I tried to set the file path as an environment variable but when notepad opens it looks for %file%.txt instead of text.txt
Any idea why?
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.EnableRaisingEvents=false;
proc.StartInfo.EnvironmentVariables.Add("file", "c:\\text.txt");
proc.StartInfo.UseShellExecute = false;
proc.StartInfo.FileName = "notepad";
proc.StartInfo.Arguments="%file%";
proc.Start();
proc.WaitForExit();
Console.WriteLine(proc.ExitCode);
If your purpose is to start the editor with a .txt file (like the title of the question says) just use:
Process.Start("C:\\text.txt")