Suppose I have an XML-serializable class called Song:
[Serializable]
class Song
{
public string Artist;
public string SongTitle;
}
In order to save space (and also semi-obfuscate the XML file), I decide to rename the xml elements:
[XmlRoot("g")]
class Song
{
[XmlElement("a")]
public string Artist;
[XmlElement("s")]
public string SongTitle;
}
This will produce XML output like this:
<Song>
<a>Britney Spears</a>
<s>I Did It Again</s>
</Song>
I want to rename/remap the name of the class/object as well. Say, in the above example, I wish to rename the class Song to g. So that the resultant xml should look like this:
<g>
<a>Britney Spears</a>
<s>I Did It Again</s>
</g>
Is it possible to rename class-names via xml-attributes?
I don't wish to create/traverse the DOM manually, so I was wondering if it could be achieved via a decorator.
Thanks in advance!
UPDATE: Oops! This time I really did it again! Forgot to mention - I'm actually serializing a list of Song objects in the XML.
Here's the serialization code:
public static bool SaveSongs(List<Song> songs)
{
XmlSerializer serializer = new XmlSerializer(typeof(List<Song>));
using (TextWriter textWriter = new StreamWriter("filename"))
{
serializer.Serialize(textWriter, songs);
}
}
And here's the XML output:
<?xml version="1.0" encoding="utf-8"?>
<ArrayOfSong>
<Song>
<a>Britney Spears</a>
<s>Oops! I Did It Again</s>
</Song>
<Song>
<a>Rihanna</a>
<s>A Girl Like Me</s>
</Song>
</ArrayOfSong>
Apparently, the XmlRoot() attribute doesn't rename the object in a list context.
Am I missing something?
XmlRoot only works with XML root nodes as per the documentation (and what you would expect, given its name includes root)!
I was unable to get any of the other answers to work so kept digging...
Instead I found that the XmlTypeAttribute (i.e. [XmlType]
) and its TypeName property do a similar job for non-root classes/objects.
e.g.
[XmlType(TypeName="g")]
class Song
{
public string Artist;
public string SongTitle;
}
Assuming you apply it to the other classes e.g.:
[XmlType(TypeName="a")]
class Artist
{
.....
}
[XmlType(TypeName="s")]
class SongTitle
{
.....
}
This will output the following exactly as required in the question:
<g>
<a>Britney Spears</a>
<s>I Did It Again</s>
</g>
I have used this in several production projects and found no problems with it.