C# How to make async MessageBox that returns DialogResult?

KotkaZ picture KotkaZ · Jan 17, 2016 · Viewed 12.7k times · Source

My MessageBox is async, but how can I return DialogResult?

Here is my code:

class AsyncMessageBox
{
    private delegate void ShowMessageBoxDelegate(string strMessage, string strCaption, MessageBoxButtons enmButton, MessageBoxIcon enmImage);
    // Method invoked on a separate thread that shows the message box.
    private static void ShowMessageBox(string strMessage, string strCaption, MessageBoxButtons enmButton, MessageBoxIcon enmImage)
    {
        MessageBox.Show(strMessage, strCaption, enmButton, enmImage);
    }
    // Shows a message box from a separate worker thread.
    public void ShowMessageBoxAsync(string strMessage, string strCaption, MessageBoxButtons enmButton, MessageBoxIcon enmImage)
    {
        ShowMessageBoxDelegate caller = new ShowMessageBoxDelegate(ShowMessageBox);
        caller.BeginInvoke(strMessage, strCaption, enmButton, enmImage, null, null);
    }
}

Answer

Reza Aghaei picture Reza Aghaei · Jan 17, 2016

If you want to use the dialog result of a non-blocking message box and perform a job based on the result:

Task.Run(() =>
{
    var dialogResult=  MessageBox.Show("Message", "Title", MessageBoxButtons.OKCancel);
    if (dialogResult == System.Windows.Forms.DialogResult.OK)
        MessageBox.Show("OK Clicked");
    else
        MessageBox.Show("Cancel Clicked");
});

Note:

  • The code after Task.Run immediately runs regardless of messagebox.