I'm following this tutorial on winforms, and so far the tutorial is coding the form without using the toolbox. I believe it'll introduce the toolbox in more depth shortly.
Following the tutorial, I've made a partial class in the following two pieces of code:
First file:
using System;
using System.Windows.Forms;
public class Numeric : System.Windows.Forms.TextBox
{
public Numeric()
{
}
}
public partial class Exercise
{
private Numeric txtbox;
System.ComponentModel.Container components;
}
Second file:
using System;
using System.Windows.Forms;
public partial class Exercise : Form
{
private void InitializeComponent()
{
txtbox = new Numeric();
Controls.Add(txtbox);
}
public Exercise()
{
InitializeComponent();
}
}
public class program
{
public static int Main()
{
Application.Run(new Exercise());
return 0;
}
}
When I run the code with F5, everything looks fine: The form pops up with the textbox.
But for some reason, when I right-click on the second file and choose "View Designer", I get an error which says "The variable 'txtbox' is either undeclared or was never assigned". I can choose to "Ignore and Continue", which leads me to a form with no textbox on it.
Why does this occur? I know some of you think I should just use the toolbox, and it's probably the most sensible thing to do, but I would still like to understand why this happens.
When you open a Form
in windows forms designer, the designer looks into the first class in the file. If the file has a Designer.cs
containing the other partial part of the class, also includes it and tries to deserialize those file contents. In the process of deserialization and loading the design time of your form, it creates an instance of the base class of your form and looks in those files for component declarations and InitializeComponents
method. If find them creates components and sets properties of them using deserialized codes and add components to the instance of base class which created.
Some useful facts:
Form
will not execute at design-time, but the constructor of base class of your form will execute in design-time.InitializeComponent
will not execute at design-time, but those codes will be deserialized and will be used to create designer of the form.MyForm:SomeForm<SomeClass>
, but it can show SomeForm<T>:Form
. (solution)Example
Take a look at below code, which has some serious problems:
int i="x";
InitializeComponent
method didn't call in constructorBut the interesting news is you can see the form in designer, even with those errors!
Just create a file in your project and put below codes in the file and save the file and close it. Then without trying to build the solution, open the form in designer. Here is code:
using System
using System.Windows.Forms
namespace SampleApplication
{
public class MyForm:Form
{
public NotMyForm()
{
}
public void InitializeComponent()
{
int i="x";
textBox1 = new TextBox()
textBox1.Text = "Hi"
this.Controls.Add(textBox1)
}
private TextBox textBox1
}
}
And here is screenshot of designer:
More information
To find more information, take a look at this link:
Solution for your question
As a solution, it is enough for you to move private Numeric txtbox;
and put it your seccond file in Exercise
class.