I am serializing List of objects List<TestObject>
, and XmlSerializer generates <ArrayOfTestObject>
attribute, I want rename it or remove it.
Can it be done with creating new class that encapsulated List as field?
[XmlRoot("Container")]
public class TestObject
{
public TestObject() { }
public string Str { get; set; }
}
List<TestObject> tmpList = new List<TestObject>();
TestObject TestObj = new TestObject();
TestObj.Str = "Test";
TestObject TestObj2 = new TestObject();
TestObj2.Str = "xcvxc";
tmpList.Add(TestObj);
tmpList.Add(TestObj2);
XmlWriterSettings settings = new XmlWriterSettings();
settings.OmitXmlDeclaration = true;
settings.Indent = true;
XmlSerializer serializer = new XmlSerializer(typeof(List<TestObject>));
using (XmlWriter writer = XmlWriter.Create(@"C:\test.xml", settings))
{
XmlSerializerNamespaces namespaces = new XmlSerializerNamespaces();
namespaces.Add(string.Empty, string.Empty);
serializer.Serialize(writer, tmpList, namespaces);
}
<ArrayOfTestObject>
<TestObject>
<Str>Test</Str>
</TestObject>
<TestObject>
<Str>xcvxc</Str>
</TestObject>
</ArrayOfTestObject>
The most reliable way is to declare an outermost DTO class:
[XmlRoot("myOuterElement")]
public class MyOuterMessage {
[XmlElement("item")]
public List<TestObject> Items {get;set;}
}
and serialize that (i.e. put your list into another object).
You can avoid a wrapper class, but I wouldn't:
class Program
{
static void Main()
{
XmlSerializer ser = new XmlSerializer(typeof(List<Foo>),
new XmlRootAttribute("Flibble"));
List<Foo> foos = new List<Foo> {
new Foo {Bar = "abc"},
new Foo {Bar = "def"}
};
ser.Serialize(Console.Out, foos);
}
}
public class Foo
{
public string Bar { get; set; }
}
The problem with this is that when you use custom attributes you need to be very careful to store and re-use the serializer, otherwise you get lots of dynamic assemblies loaded into memory. This is avoided if you just use the XmlSerializer(Type)
constructor, as it caches this internally automatically.