LINQ Distinct operator, ignore case?

c# linq string comparison distinct
Ash picture Ash · Nov 12, 2008 · Viewed 40.2k times · Source

Given the following simple example:

    List<string> list = new List<string>() { "One", "Two", "Three", "three", "Four", "Five" };

    CaseInsensitiveComparer ignoreCaseComparer = new CaseInsensitiveComparer();

    var distinctList = list.Distinct(ignoreCaseComparer as IEqualityComparer<string>).ToList();

It appears the CaseInsensitiveComparer is not actually being used to do a case-insensitive comparison.

In other words distinctList contains the same number of items as list. Instead I would expect, for example, "Three" and "three" be considered equal.

Am I missing something or is this an issue with the Distinct operator?

Answer

Marc Gravell picture Marc Gravell · Nov 12, 2008

StringComparer does what you need:

List<string> list = new List<string>() {
    "One", "Two", "Three", "three", "Four", "Five" };

var distinctList = list.Distinct(
    StringComparer.CurrentCultureIgnoreCase).ToList();

(or invariant / ordinal / etc depending on the data you are comparing)

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