How can Color.FromArgb take Int32 as parameter?

c# colors argb
user1151923 picture user1151923 · Sep 11, 2014 · Viewed 15.3k times · Source

The Color.FromArgb method takes Int32 as a parameter. The value of Color.White is #FFFFFFFF as ARGB, which is 4.294.967.295 as decimal (way over int.MaxValue). What am I not understanding here? How can the method take int as a parameter if valid ARGB values are above the maximum value of an int?

Answer

Daws picture Daws · Sep 11, 2014

Unfortunately, since Color.FromArgb takes an int instead of a uint, you will need to use the unchecked keyword for colors that are greater than int.MaxValue.

var white = Color.FromArgb(unchecked((int)0xFFFFFFFF));

Related questions

Implementing ToArgb()

System.Drawing.Color has a ToArgb() method to return the Int representation of the color. In Silverlight, I think we have to use System.Windows.Media.Color. It has A, R, G, B members, but no method to return a …

Read More
Converting hexadecimal color to integer

This is my integer color in database : "8689404". I change it to Color as following: Color = ColorHelper.FromArgb(255, byte.Parse(Event.LABELCOLOR.Value.ToString("X8").Substring(6, 2), NumberStyles.HexNumber), byte.Parse(Event.LABELCOLOR.Value.ToString("X8").Substring(4, 2), NumberStyles.HexNumber), byte.Parse(Event.…

Read More
How do I get the color from a hexadecimal color code using .NET?

How can I get a color from a hexadecimal color code (e.g. #FFDFD991)? I am reading a file and am getting a hexadecimal color code. I need to create the corresponding System.Windows.Media.Color instance for the hexadecimal …

Read More