Creating Unique Index with Entity Framework 6.1 fluent API

John picture John · May 27, 2014 · Viewed 31.3k times · Source

I have a column "Name" that must be unqiue. No foreign key or anything like that.

EF 6.1 finally supports creating such indexes via Annotations. That has been discussed already on SO. But it seems it can only be done via annotations in the classes. How do I do that using only the Fluent API?

Something like this:

public class PersonConfiguration : EntityTypeConfiguration<Person>
{
    public PersonConfiguration()
    {
        HasKey(p => p.Id);
        Property(p => p.Id).HasDatabaseGeneratedOption(DatabaseGeneratedOption.Identity);

        //not possible?
        Index(p => p.Name).IsUnique();  //???
    }
}

Answer

Anatolii Gabuza picture Anatolii Gabuza · May 27, 2014

NOTE: Relevant to EF 6

You can use IndexAttribute as mentioned but with Fluent API instead of DataAnnotations which will do the trick:

modelBuilder 
    .Entity<Person>() 
    .Property(t => t.Name) 
    .HasColumnAnnotation( 
        "Index",  
        new IndexAnnotation(new IndexAttribute("IX_Name") { IsUnique = true }));

Unfortunately there is no other way to create unique indexes using Fluent API. There is an open issue regarding this feature: Unique Constraints (Unique Indexes)


UPDATE: Entity Framework Core

In the latest EF Core release you can rely on Fluent API to specify indexes without additional tricks.
HasIndex allows to define it:

modelBuilder 
    .Entity<Person>()
    .HasIndex(x => x.Name);

Hence it returs IndexBuilder object you can use it for further index configurations (i.e uniqueness):

modelBuilder 
    .Entity<Person>()
    .HasIndex(x => x.Name)
    .IsUnique();