Error : Index was outside the bounds of the array.

Zain picture Zain · Feb 11, 2014 · Viewed 343.2k times · Source

I'm aware of what the issue is stating but I am confused to how my program is outputting a value that's outside of the array..

I have an array of ints which is 0 - 8 which means it can hold 9 ints, correct? I have an int which is checked to make sure the users input value is 1-9. I remove one from the integer (like so)

if (posStatus[intUsersInput-1] == 0) //if pos is empty
{
    posStatus[intUsersInput-1] += 1; 
}//set it to 1

then I input 9 myself and I get the error. It should access the last int in the array, so I don't see why I'm getting an error. Relevant code:

public int[] posStatus;       

public UsersInput()    
{    
    this.posStatus = new int[8];    
}

int intUsersInput = 0; //this gets try parsed + validated that it's 1-9    

if (posStatus[intUsersInput-1] == 0) //if i input 9 it should go to 8?    
{    
    posStatus[intUsersInput-1] += 1; //set it to 1    
} 

Error:

"Index was outside the bounds of the array." "Index was outside the bounds of the array."

Answer

M.S. picture M.S. · Feb 11, 2014

You have declared an array that can store 8 elements not 9.

this.posStatus = new int[8]; 

It means postStatus will contain 8 elements from index 0 to 7.