How to avoid error "Constructor on type 'MyType' not found" when inheriting a base class

Jed picture Jed · May 1, 2013 · Viewed 15.9k times · Source

I have a Visual Studio 2010 Windows Forms app which includes a Form base class that other classes will inherit. The base class' constructor takes a parameter that the child classes will pass to the base class.

Example:

public partial class BaseForm : Form
{
    public BaseForm(int number)
    {
        InitializeComponent();
    }
}

public partial class ChildForm : BaseForm
{
    public ChildForm(int number)
        : base(number)
    {
        InitializeComponent();
    }
}

The problem that I'm running into is, when I attempt to open the ChildForm in VisualStudio's Design View mode, I receive the following error:

Constructor on type 'MyProject.BaseForm' not found.

Note: regardless of the error, the project compiles and runs fine.

I can avoid the error if I overload the constructor with one that does not contain any parameters.

Example: (This gets rid of the error)

public partial class BaseForm : Form
{
    public BaseForm(int number)
    {
        InitializeComponent();
    }

    public BaseForm()
    {
        InitializeComponent();
    }
}

public partial class ChildForm : BaseForm
{
    public ChildForm(int number)
        : base(number)
    {
        InitializeComponent();
    }
}

My question is, how can I create a base class that does not include a parameterless constructor and avoid the Design View error?

Answer

SLaks picture SLaks · May 1, 2013

That is completely impossible.

The form you see in the design view is an actual instance of your base class.
If there is not default constructor, the designer cannot create that instance.

You can mark the constructor with the [Obsolete("Designer only", true)], and make it throw an exception if called when not in the designer, to prevent other people from calling it.