Wpf DataGrid Add new row

Mandar Jogalekar picture Mandar Jogalekar · Apr 27, 2013 · Viewed 151.5k times · Source

I have managed to get DataGrid to show new row for adding new item. Problem i face now is i want data in the rest of wpf DataGrid to be read only and only new row should be editable.

Currently this is how my DataGrid looks.

<DataGrid AutoGenerateColumns="False" Name="DataGridTest" CanUserAddRows="True" Grid.Row="2" ItemsSource="{Binding TestBinding}" >
    <DataGrid.Columns>        
        <DataGridTextColumn Header="Line" IsReadOnly="True" Binding="{Binding Path=Test1}" Width="50"></DataGridTextColumn>
        <DataGridTextColumn Header="Account" IsReadOnly="True"  Binding="{Binding Path=Test2}" Width="130"></DataGridTextColumn>               
    </DataGrid.Columns>
</DataGrid>

But since I have kept the columns read only, a new row also adds as read only which is what I don't want.

Answer

Elyor picture Elyor · Apr 27, 2013

Try this MSDN blog

Also, try the following example:

Xaml:

   <DataGrid AutoGenerateColumns="False" Name="DataGridTest" CanUserAddRows="True" ItemsSource="{Binding TestBinding}" Margin="0,50,0,0" >
        <DataGrid.Columns>
            <DataGridTextColumn Header="Line" IsReadOnly="True" Binding="{Binding Path=Test1}" Width="50"></DataGridTextColumn>
            <DataGridTextColumn Header="Account" IsReadOnly="True"  Binding="{Binding Path=Test2}" Width="130"></DataGridTextColumn>
        </DataGrid.Columns>
    </DataGrid>
    <Button Content="Add new row" HorizontalAlignment="Left" Margin="0,10,0,0" VerticalAlignment="Top" Width="75" Click="Button_Click_1"/>

CS:

 /// <summary>
/// Interaction logic for MainWindow.xaml
/// </summary>
public partial class MainWindow : Window
{
    public MainWindow()
    {
        InitializeComponent();
    }

    private void Button_Click_1(object sender, RoutedEventArgs e)
    {
        var data = new Test { Test1 = "Test1", Test2 = "Test2" };

        DataGridTest.Items.Add(data);
    }
}

public class Test
{
    public string Test1 { get; set; }
    public string Test2 { get; set; }
}