Why is it faster to check if dictionary contains the key, rather than catch the exception in case it doesn't?

Question

Imagine the code:

public class obj
{
    // elided
}

public static Dictionary<string, obj> dict = new Dictionary<string, obj>();

Method 1

public static obj FromDict1(string name)
{
    if (dict.ContainsKey(name))
    {
        return dict[name];
    }
    return null;
}

Method 2

public static obj FromDict2(string name)
{
    try
    {
        return dict[name];
    }
    catch (KeyNotFoundException)
    {
        return null;
    }
}

I was curious if there is a difference in performance of these 2 functions, because the first one SHOULD be SLOWER than second one - given that it needs to check twice if the dictionary contains a value, while second function does need to access the dictionary only once but WOW, it's actually opposite:

Loop for 1 000 000 values (with 100 000 existing and 900 000 non existing):

first function: 306 milliseconds

second function: 20483 milliseconds

Why is that?

EDIT: As you can notice in comments below this question, the performance of second function is actually slightly better than first one in case there are 0 non existing keys. But once there is at least 1 or more non existing keys, the performance of second one decrease rapidly.

Answer 1

On the one hand, throwing exceptions is inherently expensive, because the stack has to be unwound etc.
On the other hand, accessing a value in a dictionary by its key is cheap, because it's a fast, O(1) operation.

BTW: The correct way to do this is to use TryGetValue

obj item;
if(!dict.TryGetValue(name, out item))
    return null;
return item;

This accesses the dictionary only once instead of twice.
If you really want to just return null if the key doesn't exist, the above code can be simplified further:

obj item;
dict.TryGetValue(name, out item);
return item;

This works, because TryGetValue sets item to null if no key with name exists.