Add a row to an existing table in a Word Document (open XML)

Question

I need to open an existing Word document (.docx) with an existing table (with, for example, 3 columns) and add a new row to that table. Is there any way of doing this? I am using Open XML

I am creating the table like this (for the first time):

Table tbl = new Table();

// Set the style and width for the table.
TableProperties tableProp = new TableProperties();
TableStyle tableStyle = new TableStyle() { Val = "TableGrid" };

// Make the table width 100% of the page width.
TableWidth tableWidth = new TableWidth() { Width = "5000", Type = TableWidthUnitValues.Pct };

// Apply
tableProp.Append(tableStyle, tableWidth);
tbl.AppendChild(tableProp);

// Add 3 columns to the table.
TableGrid tg = new TableGrid(new GridColumn(), new GridColumn(), new GridColumn());
tbl.AppendChild(tg);

// Create 1 row to the table.
TableRow tr1 = new TableRow();

// Add a cell to each column in the row.
TableCell tc1 = new TableCell(new Paragraph(new Run(new Text("1"))));
TableCell tc2 = new TableCell(new Paragraph(new Run(new Text("2"))));
TableCell tc3 = new TableCell(new Paragraph(new Run(new Text("3"))));
tr1.Append(tc1, tc2, tc3);

// Add row to the table.
tbl.AppendChild(tr1);
return tbl;

Answer 1

Here you go,

Body bod = doc.MainDocumentPart.Document.Body;
foreach (Table t in bod.Descendants<Table>())
{
    t.Append(new TableRow(new TableCell(new Paragraph(new Run(new Text("test"))))));
}

Use LINQ to get the proper table.

EDIT:

Say you want to get the table that has 4 columns.

Body bod = doc.MainDocumentPart.Document.Body;
foreach (Table t in bod.Descendants<Table>().Where(tbl => tbl.GetFirstChild<TableRow>().Descendants<TableCell>().Count() == 4))
{
    t.Append(new TableRow(new TableCell(new Paragraph(new Run(new Text("test"))))));
}

Say you want to get the table that contains the word "mytable".

Body bod = doc.MainDocumentPart.Document.Body;
foreach (Table t in bod.Descendants<Table>().Where(tbl => tbl.InnerText.Contains("myTable")))
{
    t.Append(new TableRow(new TableCell(new Paragraph(new Run(new Text("test"))))));
}